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Q.

The density in g mL−1 of  a 3.60M sulphuric acid solution that is 29% H2SO4molar mass=98g mol−1by  mass will be

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a

2.212

b

1.216

c

3.4

d

4.5

answer is B.

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Detailed Solution

molarity=weight of solute×1000gram molecular weight×volume of solution in mlLet us consider 100 gm of the solution = 100/d ml of solutionIn 100 gm of solution, mass of the solute present = 29 gm3.6 = 29×1000×d98×100 d = 1.216 gm/ml
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The density in g mL−1 of  a 3.60M sulphuric acid solution that is 29% H2SO4molar mass=98g mol−1by  mass will be