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Q.

Density of an ideal gas at 2 atm and 600 K is 2 g/L.Calculate relative density of this gas with respect to Ne(g) at same conditions :(Given : R =1/72 atm L/mol.K)

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a

2.5

b

2

c

3

d

5

answer is A.

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Detailed Solution

PM=dRT⇒MGas=2×0.0821×6002=49.26At const, P and T d∝MdGasdNe=MGasMNe=49.2620=2.463≅2.5
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