First slide

Gaseous state

Question

The density of phosphorus vapour at STP is 5.54 gL^-1. Hence, molecular formula of phosphorus is

Moderate

A

$P_{2}$
B

P₃
C

P₄
D

P₈

Solution

$d = \frac{pm}{RT} m (phosphorus) = \frac{dRT}{p}$
$= \frac{5 .54 \times 0 .0821 \times 273}{1}$
$= 124 .1 g {mol}^{- 1}$
$If molecular formula is {(p)}_{x} then 32 x = 124 .1 x = 4 Hence, P_{4} .$

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