Q.

The density of a solution containing 13% by mass of sulphuric acid is 1.09 g/mL. Calculate the molarity and normality of the solution

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1.445 M and 2.89N

14.45 M and 28.9N

144.5 M and 289 N

0.1445 M and 0.289 N

answer is A.

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Detailed Solution

Volume of 100 g of the solution =100d=1001.09mL=1001.09×1000litre=11.09×10 litreNumber of moles of H2SO4 in 100 g of the solution =1398Molarity =No. of moles of SoluteVolume in litre=1398×1.09×101=1.445M ORM = M =%×d×10GMW M = 13×1.09 ×1098 M =1.445MN = M ×basicity of acidN = 1.445 ×2 = 2.89

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