The density of a solution prepared by dissolving 120 g of urea (mol. Mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity if this solution is

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0.50 M

1.78 M

1.02 M

2.05 M

answer is D.

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Detailed Solution

Total mass of solution = 1000 g water + 120 g urea = 1120 gDensity of solution = 1.15 g/mLThus, volume of solution = massdensity = 1120 g1.15 g/mL = 973.91 mL = 0.974 LMoles of solute = 12060=2 molMolarity=moles of solutevolumeL of solution=2 mol0.974 L=2.05 mol L−1

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