Determine the equivalent weight of K2Cr2O7 in the reaction, K2Cr2O7+7H2SO4+6FeSO4⟶Cr2SO43+K2SO4+3Fe2SO43+7H2O

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answer is 49.

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Detailed Solution

The given reaction may be written as, Cr2O72−+14H++6Fe2+⟶2Cr3++6Fe3++7H2OThus, Cr6+ in Cr2O72− undergoes reduction to Cr3+, and Fe2+ gets oxidized to Fe3+. The reaction stoichiometry gives:K2Cr2O7≡Cr2O72−≡2Cr6+That is 1 mol of potassium dichromate is equivalent to 2Cr6+ ions. Each Cr6+ ion gains 3 electrons to give Cr3+. Therefore, one molecule of K2Cr2O7 gains six electrons to get reduced to two Cr3+ ions. As per definition, for this reaction, Equivalent weight of K2Cr2O7.= Molecular mass of K2Cr2O76 =(2×39×+2×52+7×16)6 =78+104+1126=2946=49

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