Determine the osmotic pressure of the solution prepared by dissolving 25 mg of K2SO4 in 2L of water at 25oC. (Assuming it is to be completely dissociated)

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5.27 x 10-4 atm

5.27 x 10-3 atm

5.27 x 10-2 atm

5.27 x 10-1 atm

answer is B.

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Detailed Solution

K2SO4 dissolved = 25 mg = 0.025 gVolume = 2 L; Temperature, T = 298 KMolar mass of K2SO4 = 174 g mol-1K2SO4 dissociates into 2 K+ and SO42-ions, so i = 3π=iCRTπ=i×wM×RTV =3×0.025174×12×0.0821×298 =5.27×10−3atm

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