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Determine the oxidation number of Fe element in the following compoundFeSO4NH42SO4⋅6H2O

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answer is 2.

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Detailed Solution

FeSO_4NH42SO4⋅6H2O:Oxidation number of Fe = aSum of oxidation number for NH42SO4=0 Sum of oxidation number of H2O = 0Sum of oxidation number of SO42−=−2∴ a+(−2)+0+6(0)=0⇒a=+2

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