Determine whether or not it is possible for sodium to reduce aluminum oxide to aluminum at 298 K. Also calculate equilibrium constant. Given that Gfo of Al2O3 at 298K=−1582kJmol−1;Gf∘ of Na2O(s) at 298K=− 377 kJ mol-1.

The given reaction is:Al2O3(s)+6Na(s)→3NaO(s)+2Al(s) Hence, ΔG∘=3×Gf∘Na2O−Gf∘Al2O3G∘ for Na and Al=0=3×(−377)−(−1582)=+451kJmol−1 The reaction cannot occur since ΔG∘(298K) is positive  Also ΔG∘=−2.303RTlog10⁡K451=−2.303×8.314×10−3×298log10⁡K - log⁡K=−79.04K=9.1×10−80