First slide

Group 14 or carbon family

Question

In diamond and graphite the percentage of S-characters of the Hybrid orbitals in Hybridization are respectively

Moderate

A

75 and 25
B

50 and 50
C

25 and 33
D

25 and 75

Solution

Carbon hybridization in diamond is ${SP}^{3}$ carbon Hybridization in graphite is ${SP}^{2}$
$\begin{array}{l} % S in {SP}^{3} = \frac{1}{4} \times 100 = 25 % \\ % S in {SP}^{2} = \frac{1}{3} \times 100 = 33.33 % \approx 33 \end{array}$

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