First slide

13th group or boron group

Question

Diborane reacts with NaH to give ___?

Easy

A

$N a [B H_{4}]$
B

$N a B H_{2}$
C

$N a B H_{3}$
D

All the above

Solution

The following is an important preparation method of a very important complex hydride.
$2 N a H + B_{2} H_{6} \to 2 N a [B H_{4}]$
It is a good reducing agent in organic chemistry.

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