First slide

13th group or boron group

Question

Diborane reacts with NaH gives

Moderate

A

$Na [{BH}_{4}]$
B

${NaBH}_{2}$
C

${NaBH}_{3}$
D

All the above

Solution

$2 NaH + B_{2} H_{6} \to 2 Na [{BH}_{4}]$

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