Q.

The difference between the boiling point and freezing point of an aqueous solution containing sucrose (molecular weight = 3429 mol-1 ) in 100 g of water is 105.0oC. If Kb and K 6 of water are 1.86 and 0.51 K kg mol-1 respectively, the weight of sucrose in the solution is about

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a

34.2 g

b

342 g

c

7.2 g

d

72 g

answer is D.

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Detailed Solution

Given, Tb-Tf=105.0oC ⇒  100-∆Tb-0-∆Tf=105oC                          ∆Tb+∆Tf=5                           ∆Tb+∆Tf=Kb+Kf×m;m=molality ⇒                          5= 1.86+0.51×w×1000342×100 ∴  On solving,w=72 g
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