The difference between the boiling point and freezing point of an aqueous solution containing sucrose (molecular weight = 3429 mol-1 ) in 100 g of water is 105.0oC. If Kb and K 6 of water are 1.86 and 0.51 K kg mol-1 respectively, the weight of sucrose in the solution is about
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a
34.2 g
b
342 g
c
7.2 g
d
72 g
answer is D.
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Detailed Solution
Given, Tb-Tf=105.0oC ⇒ 100-∆Tb-0-∆Tf=105oC ∆Tb+∆Tf=5 ∆Tb+∆Tf=Kb+Kf×m;m=molality ⇒ 5= 1.86+0.51×w×1000342×100 ∴ On solving,w=72 g