Q.

The difference between the heat of reaction at constant pressure and constant volume  for the reaction2C6H6l + 15O2g  →  12CO2g+6H2Ol at 250C in kJ is

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a

-7.43

b

3.72

c

-3.72

d

7.43

answer is A.

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Detailed Solution

For the reaction2C6H6l + 15O2g  → 12CO2g+6H2OlHere ∆ng=12-15=-3 As we know,  ∆H = ∆E+∆ngRT or, ∆H-∆E=∆ngRT = -3 × 8.314 × 298 = -7.43 kJ
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The difference between the heat of reaction at constant pressure and constant volume  for the reaction2C6H6l + 15O2g  →  12CO2g+6H2Ol at 250C in kJ is