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Q.

The difference between the heat of reaction of constant pressure and constant volume for the reaction2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) at 25∘C in kJ is

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a

-7.43

b

3.72

c

-3.72

d

7.43

answer is A.

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Detailed Solution

For the reaction2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) Here Δn=12−15=−3 As we know, ΔH=ΔE+ΔnRT or, ΔH−ΔE=ΔnRT=−3×8.314×298=−7.43kJ

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