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The difference between the heats of reaction at constant pressure and a constant volume for the reaction2C6H6(l)+15O2( g)⟶12CO2( g)+6H2O(l) at 25°C in KJ is

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An Intiative by Sri Chaitanya

a

7.43 kJ

b

-7.43 J

c

74.3 J

d

-7.43 kJ

answer is D.

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Detailed Solution

ΔH=ΔU+ΔngRT here Δng=12-15=-3 Thus ΔH-ΔU=ΔngRT =-3×8.314×10-3×298=-7.43KJ

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