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Q.

The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times. As a result, the diffusion coefficient of this gas increases x times. The value of x is

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answer is 4.

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Detailed Solution

Mean free path =K⋅T2πd2⋅p Meen speed =8RTMπDαT3/2P⇒D1D2=T1T23/2⋅P2P1⇒D1D2=T14T13/2−2P1P1=143/2.2D1D2=123⋅2D1D2=14D2=4D1

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