In the disproportionate reaction3HClO3⟶HClO4+Cl2+2O2+H2Othe equivalent mass of the oxidising agent is: (molar mass) of HCIO3 = 84.45)

We know that, equivalent mass = Molar mass/oxidation number change.Oxidation no. of Cl in HCIO3 . O.N. of H+O.N. of Cl+3×O.N. of O=0;+1+x+3(−2)+0;x=+5O.N. of Cl in Cl2 = 0. So, O.N. change= 5- 0 = 5 Equivalent mass = Molar mass/O.N. change = 84.45/5 i.e., 16.89So, the correct answer is (1).