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The dissociation constant of a monobasic acid which is 3.5% dissociated in solution at is
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By Expert Faculty of Sri Chaitanya
a
3.5× 10-2
b
5× 10-3
c
6.34× 10-5
d
6.75× 10-2
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Correct option is C
Concentration of acid = N20 = 0.05 NOut of 100 molecules, 3.5 molecules has been dissociated α=35100 =0.035 Ka= Cα21-α = 0.05× 0.03521-0.035 = 6.34× 10-5
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