The dissociation constant of a weak acid is 1.0 × 10-5, the equilibrium constant for the reaction with strong base is

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1.0 × 10-5

1.0 × 10-9

1.0 × 109

1.0 × 1014

answer is C.

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Detailed Solution

HA ⇌ H+ + A- ; Ka = H+ A-HANeutralization of the weak acid with strong base is HA + OH- ⇌ A- + H2OK =A-HA OH-Dividing (i) by (ii), KaK = H+ OH- Given , Ka = 10-5K = KaKw =10-510-14 = 109

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