The dissociation constant of weak acid HA is 4.9× 10-8. After making the necessary approximations, calculate pH of 0.1 M acid.

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1.155

2.155

3.155

4.155

answer is D.

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Detailed Solution

For weak acid Ka =C α2.∴ α = KaC = 4.9× 10-80.1 = 7× 10-4[ H+]=Cα PH=-log [ H+]=-log Cα =-log 7× 10-4× 10-1 = 4.1549 = 4.155

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