Q.
Dissociation constants of two acids HA and HB are respectively 4 × 10-10 and 4 × 10-5, whose pH value will be higher for a given molarity
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a
HA
b
HB
c
Both same
d
Can't say
answer is A.
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Detailed Solution
HA ⇌ H++A-HB ⇌ H++B-For HAKa = α2Cα1 = Ka1C = 4 × 10-101α1 = 2 × 10-5 for C = 1 MSimilarly ⇒ H+ = Cα = 2 × 10-5 ; pH =-log [H+] = 4.7For HB: α2 = Ka2C = 1.8 × 10-51 for C = 1 Mα2 = 4.2 × 10-3 ⇒ H+=Cα = 4.2 × 10-3 pH =-log 4.2 × 10-3 = 2.37 ; PH of HA>HB
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