First slide

Enthalpy of Atomisation and bond dissociation

Question

The dissociation energy of CH₄ is 400K.Cal mol^–1 and that of ethane is 670 K.Cal mol^–1. The C–C bond energy is:

Moderate

A

270K.Cal
B

70K.Cal
C

200K.Cal
D

240K.Cal

Solution

$\large B{E_{C{H_4}}}\; = \;4B{E_{C - H}}\; = \;400\;Kcal\$
$\large B{E_{C - H}}\; = \;100\;Kcal\$
$\large B{E_{{C_2}{H_6}}}\; = \;B{E_{C - C}}\; + \;6B{E_{C - H}}\$
$\large 670\; = \;B{E_{C - C}}\; + \;6(B{E_{C - H}})$
$\large 670\; = \;B{E_{C - C}}\; + \;6(100)\$
$\large B{E_{C - C}}\; = 670 - 600 = \;70Kcal\$

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