Dissolution of 1.5 g of a non-volatile solute (molecular weight = 60) in 250 g of a solvent reduces its freezing point by 0.01o C. Find at the molal depression constant of the solvent.

Depression in freezing point, ∆Tf=Kf×mwhere, m = molality =weight of solute x 1000molecular weight of solute x weight of solvent                               =1.5×100060×250=0.1                           ∆Tf=Kf×0.1⇒0.01=Kf×0.1 ∴     Kf=0.010.1=0.1