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Q.

On dissolving CO2 in water, the following equilibrium is establishedCO2+2H2O⇌H3O++HCO3−for which the value of equilibrium constant is 3 .8 x 10-7 andpH = 6.0. The HCO3−CO2 ratio is

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a

3.8

b

0.38

c

13.8

d

1.38

answer is B.

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Detailed Solution

pH=pKa+logHCO3−CO2 6.0=−log3.8×10−7+logHCO3−CO2 6.0=+6.42+logHCO3−CO2 ∴ logHCO3−CO2=−0.42 ∴ HCO3−CO2=0.38
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