Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

Molarity (M)= Moles of solute  Volume of solution (in L)  Moles of urea =12060=2Weight of solution = Weight of solvent + Weight of solute                          = 1000 +120= 1l20g⇒  Volume =1120 g1.15×11000 mL=0.973 L∴  Molarity =20.973=2.05M