First slide

Liquid state

Question

Distribution coefficient of solute X between ether and water is 2.1 g of solute X is in 100 g water. If X is extracted into ether by 100 mL of it, then

Difficult

A

0.667 g of Xis extracted into ether, if it is used in one part of 100 mL
B

0.75 g of X is extracted into ether, if it is used in two parts of 50 mL each
C

Both (a) and (b)
D

None of the above

Solution

$If W_{n} = solute extracted into solvent II by n extractions$
w = solute initially in solvent I
$V_{1} = volume of solvent$
$V_{2} = volume of solvent II to be used in n parts$
$\frac{C_{2}}{C_{1}} = K (Partition coefficient)$
$then W_{n} = W - w {(\frac{{nV}_{1}}{{nV}_{1} + {KV}_{2}})}^{n}$
$(I) If n = 1, V_{1} = 100 mL, V_{2} = 100 mL, w = 1 g, K = 2$
$then w_{1} = 1 - 1 (\frac{1}{3}) = \frac{2}{3} = 0 .667$
Thus, (a) is true
$(II) If n = 2, V_{1} = 100 mL, V_{2} = 100 mL, w = 1 g, K = 2$
$then w_{2} = 1 - 1 {(\frac{1}{2})}^{2} = \frac{3}{4} = 0 .75 g$
Thus, (b) is also true

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App