A drop of solution (volume 0.05 mL) contains 3.0×10−6 moles of H+. If the rate constant of disappearance of H+ is 1.0×107 mole litre−1sec⁡−1. How long would it take for H+ in drop to disappear:

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6×10−8sec⁡

6×10−7sec⁡

6×10−9sec⁡

6×10−10sec⁡

answer is C.

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Detailed Solution

Units rate constant=mol L−1sec⁡−1⇒Zero order reaction. H+=3×10-6×10000.05 =0.06 mol.L-1 t=xK = 6×10-2107 =6×10-9sec

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