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Q.

Dry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04 g. The molecular weight of the solute is:

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a

31.25

b

3.125

c

312.5

d

None of these

answer is A.

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Detailed Solution

P0−PS∝ loss in weight of water chamber and   PS  ∝   loss in weight of solution chamber. Po−PsPo=nN=w×Mm×Ww1w2=Po-PSPoor 0.042.50=5×18m×180∴m=31.25
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