Dry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04 g. The molecular weight of the solute is:
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a
31.25
b
3.125
c
312.5
d
None of these
answer is A.
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Detailed Solution
P0−PS∝ loss in weight of water chamber and PS ∝ loss in weight of solution chamber. Po−PsPo=nN=w×Mm×Ww1w2=Po-PSPoor 0.042.50=5×18m×180∴m=31.25