Q.
In Duma’s method of estimation of nitrogen, 0.1840g of an organic compound gave 30mL of nitrogen collected at 287 K and 758mm of Hg pressure. The percentage composition of nitrogen in the compound is ______________ ( round off to the Nearest Integer) [given Aqueous tension at 287 K = 14 mm of Hg]
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answer is 19.
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Detailed Solution
Given conditions S.T.P conditionsP1=758-14mm =744mm of Hg P2=760mm of HgV1=30mℓ V2=?T1=287k T2=273k∴V2=P1V1T1×T2P2=744×30×273287×760=27.935ml%N=18×VN2(mℓ)W0⋅C=18×27.9350.1840 =18.97 =19
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