First slide

Electrolysis

Question

During electrolysis of fused NaOH

Easy

A

H₂ is liberated at cathode
B

O₂ is liberated at cathode
C

H₂ is liberated at anode
D

O₂ is liberated at anode

Solution

Fused NaOH
$2NaOH \rightleftharpoons 2N{a^ + } + 2O{H^ - }$
At Anode
$4O{H^ - } \to {O_2} + 2{H_2}O + 4{e^ - }$
At Cathode
$2N{a^ + } + 2{e^ - } \rightleftharpoons 2Na$

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