During electrolysis of water the volume of O2 liberated is 2.24dm3. The volume of hydrogen liberated, under same conditions will be

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2.24dm3

1.12dm3

4.48dm3

0.56dm3

answer is C.

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Detailed Solution

During electrolysis volume of O2 and H2 liberated are in the ratio of 1:2, hence volume of H2 liberated will be 4.48 dm3.

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