First slide

Corrosion

Question

During the rusting of iron

Moderate

A

metal acts as cathode
B

hydrogen ion acts as anode
C

formula of rust is ${Fe}_{3} O_{4} . {xH}_{2} O$
D

the overall reaction is $2 Fe + O_{2} + 4 H^{+} \to 2 {Fe}^{2 +} + 2 H_{2} O$

Solution

During rusting of iron, metal acts as anode, hydrogen ion as cathode. The overall reaction is $2 Fe + O_{2} + 4 H^{+} \to 2 {Fe}^{2 +} + 2 H_{2} O$ Formula of rust is ${Fe}_{2} O_{3} . {xH}_{2} O$ .

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