$E_{cell}^{\Theta }$ for some half cell reactions are given below. On the basis of these mark the correct answer.

$\text{ (1) }{H}^{+}\left(aq\right)+e^{-}\to \frac{1}{2}{H}_2\left(g\right);E_{cell}^{\Theta }=0.00V$

$\text{( ii) }2H_{2}O\left(l\right)\to O_2\left(g\right)+4H^{+}\left(aq\right)+4e^{-};E_{cell}^{\Theta }=1.23V$

$\text{ (iii) }2S{O}_4^{2-}\left(aq\right)\to S_2{O}_8^{2-}\left(aq\right)+2e^{-};E_{\text{cell }}^{\Theta }=1.96 \mathrm{V}$

• A

  In dilute sulphuric acid acid solution, hydrogen ion will be reduced at cathode

• B

  In concentrated sulphuric acid solution, water will be oxidized at anode

• C

  In dilute sulphuric acid solution, water will be oxidized at anode

• D

  in dilute sulphuric acid solution, $S{O}_4^{2-}$ion will be oxidized to tetrathionate ion at anode.