ECu2+∣Cu0=+0.34VEZn2+∣Zn0=−0.76VIdentify the incorrect statement from the options below for the above cell

Since Anode and cathode are in standard conditions Ecell =Ecell ∘=1.1V1) Since Eext  is opposiving the emf of galvanic cell if Eext=1.1V  then no net current will flow (correct)2) If Eext<1.1V  then zinc will act as cathode and Cu as anode. Zn will dissolve and Cu will deposit (correct)3) If Eext>1.1V then oxidation takes place at Cu and reduction takes place at Zn. Electron will move from copper to zinc. (correct)4) Since (2) is correct (4) is wrong