First slide
Electrochemical cell
Question

E0 for F2 +2e- 2F-  is 2.8     
E0 for 12F2 +e- F- is

Easy
Solution

Electrode potentials are intensive properties .

E = {E^o} - \frac{{0.0591}}{1}\log \frac{{\left[ {{F^ - }} \right]}}{\left[ {{F_2}} \right]^{\frac{1}{2}}}

= {E^o} = 2.8V

Since [F-] = 1M and pressure of F2 =1 atm

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