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Q.

For EoZn2+/zn= - 0. 76 V the E.M.F of the cell  Pt(s)H2(g)(lbar)H+(aq)1M||Zn2+(aq)1(M)∣Zn will be

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a

-0.76 V

b

0.38 V

c

0.76 V

d

-0.38 V

answer is A.

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Detailed Solution

Ecell =Ecell0−0.05912log⁡Zn2+H+2PH2Ecell =Ecell0=−0.76V
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