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${\mathrm{E}}_{\mathrm{Pt},\frac{1}{2}{\mathrm{F}}_{2}/{\mathrm{F}}^{-}}^{0}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}+2.87\mathrm{V}\text{\hspace{0.17em}};\text{\hspace{0.17em}}{\mathrm{E}}_{{\mathrm{Au}}^{+3}/\mathrm{Au}}^{0}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}+1.4\mathrm{V}$${\mathrm{E}}_{{\mathrm{Fe}}^{+3}/{\mathrm{Fe}}^{+2}}^{0}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}+0.772\mathrm{V};\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{E}}_{{\mathrm{Cu}}^{+}/\mathrm{Cu}}^{\mathrm{o}}\text{\hspace{0.17em}}=+\text{\hspace{0.17em}}0.52\mathrm{V}$Based on the above data the best oxidant is

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a
F2
b
Au+3
c
Fe+3
d
Cu+

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detailed solution

Correct option is A

SRP values of F2 > Au+3 >  Fe+3> Cu+∴Tendency to undergo reduction is F2 > Au+3> Fe+3> Cu+Oxidizing power of F2> Au+3 > Fe+3> Cu+

Similar Questions

Statement 1: Cu is less reactive than hydrogen.
Statement 2: ${\mathrm{E}}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{\mathrm{o}}$ is negative.