EA+/A0=0.5V; EB+/B0=0.2V; EC+/C0=-0.3V; ED+/D0=-0.1VBased on above data select correct statements under standard condition
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
Best oxidizing agent is A+
b
Best reducing agent is D
c
C can displace D+ from it’s solution
d
a Galvanic cell obtained by electrodes A and B shows the current flow from B to A in external circuit.
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Element lower SRP reduces ion with higher SRPThe ion with higher SRP oxidises the element with lower SRPElectrons flow from anode (B) to cathode (A) and hence current flows from A to B