The efficiency of fuel cell is 80% and the standard heat of Combustion of the fuel is ∆H=-300kJ. The redox reaction involves transaction of two electrons. E0 of the fuel cell is
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a
1.24V
b
2.48V
c
Zero V
d
0.62V
answer is A.
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Detailed Solution
Efficiency of fuel cell=ΔGΔH×100 ⇒80=ΔG−300kJ×100 ⇒ΔG=−240×103J ∴ΔG=−nFEcell0 −240×103=−2×96500×Ecell0 Ecell0=2400002×96500=1.24 V