The efficiency of fuel cell is 80% and the standard heat of reaction is -300KJ. The reaction involves two electrons in redox change. E0 for the cell is
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answer is 1.
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Detailed Solution
Efficiency of fuel cell =ΔGΔH×100⇒80=ΔG−300×100 KJ⇒ΔG=−240×103J∴ΔG=−nFE0cell⇒−240×103=−2×96500×E0cell⇒E0cell=2400002×96500=1.24v