An electric discharge is passed through a mixture containing $$50$$ c.c. of $$O2$$ and $$50$$ c.c. of $$H2$$. The volume of the gases formed (i) at room temperature and (ii) at $$1100C$$ will be

Question

An electric discharge is passed through a mixture containing $$50$$ c.c. of $$O2$$ and $$50$$ c.c. of $$H2$$. The volume of the gases formed (i) at room temperature and (ii) at $$1100C$$ will be

Infinity Learn · Accepted Answer

(i)At$$ room  temperature  $$2H2g$$ $$+$$  $$O2g$$  →  $$2H2Ol$$                                  $$2moles$$     $$1mole$$     $$2moles$$                                   $$2$$×$$22.4l$$     $$22.4l$$                                      $$50ml$$         ?$$(=25ml) given volume of $$O2=50$$ ml volume of $$O2$$ $$released(which$$ is $$unreacted)=50-25$$ $$=25ml$$ volume of gases formed at room temperature $$=$$ $$25cc(since$$ $$H2O$$ formed is $$liquid)(ii)$$ At $$110$$°c :                      $$2H2g$$ $$+$$  $$O2g$$  →  $$2H2Og$$                     $$50ml$$      $$25ml$$       $$50ml$$ volume of gases formed $$=volume$$ of $$H2O(g)$$ $$formed+volume$$ of $$O2$$ unreacted                                       $$=$$ $$50$$ $$+$$ $$25$$ $$=75ml$$

An electric discharge is passed through a mixture containing 50 c.c. of O2 and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 1100C will be

Best Courses for You

Detailed Solution

courses

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

download the app

Download the App