First slide

Faraday's Laws

Question

Electro chemical equivalent of an element is $9.33 \times 10^{- 5} g / mol .$ Equivalent weight of the element is

Easy

A

9
B

12
C

19
D

20

Solution

Weight deposited by one coulomb of electricity is E.C.E;
$E . C . E = \frac{EW}{96500}; EW = 96500 \times 9.33 \times 10^{- 5}; EW = 9;$

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