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For an electrochemical cellSns|Sn2+aq, 1M||Pb2+aq, 1M|PbsThe ratio Sn2+Pb2+  when this cell attains equilibrium is______(Given:ESn2+|Sn0=−0.14 V, EPb2+|Pb0=−0.13 V, 2.303RTF=0.06 )

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answer is 2.15.

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Detailed Solution

E0=0.062logSn+2Pb+2 0.14−0.13=0.03logSn+2Pb+2 Sn+2Pb+2=1013=2.15
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For an electrochemical cellSns|Sn2+aq, 1M||Pb2+aq, 1M|PbsThe ratio Sn2+Pb2+  when this cell attains equilibrium is______(Given:ESn2+|Sn0=−0.14 V, EPb2+|Pb0=−0.13 V, 2.303RTF=0.06 )