First slide

Nernst Equation

Question

Electrode potential for Mg electrode varies according to the equation
$E_{{Mg}^{2 +} / Mg} = E_{{Mg}^{2 +} / Mg}^{θ} - \frac{0 .059}{2} \log \frac{1}{[{Mg}^{2 +}]}$ .The graph of $E_{{Mg}^{2 +} / Mg} v_{S} \log [{Mg}^{2 +}]$ is

Moderate

A
B
C
D

Solution

Electrode potential for Mg electrode varies according to the equation,
$\begin{aligned} E_{{Mg}^{2 +} / Mg} = E_{{Mg}^{2 +} / Mg}^{\circ} - \frac{0 .059}{2} \log \frac{1}{[{Mg}^{2 +}]} \\ E_{{Mg}^{2 +} / Mg} = E_{{Mg}^{2 +} / Mg}^{\circ} + \frac{0 .059}{2} \log [{Mg}^{2 +}] \\ E_{{Mg}^{2 +} / Mg} = \frac{0 .059}{2} \log [{Mg}^{2 +}] + E_{{Mg}^{2 +} / Mg}^{\circ} \end{aligned}$
This equation represents equation of straight line. It can be correlated as
$\begin{array}{ccc} E_{{Mg}^{2 +} / Mg} = & (\frac{0 .059}{2}) & \log [{Mg}^{2 +}] + E_{{Mg}^{2 +} / Mg}^{\circ} \\ ↑ & ↑ & ↑ & ↑ \\ Y & m & x & + C \end{array}$
So, intercept $(C) = {E_{{Mg}^{2 +} /}}_{Mg}$

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