First slide

Faraday's Laws

Question

Electrolysis of aq. $K_{2} {SO}_{4}$ using inert electrodes is carried out by passing 9650 coulombs. Weight of the substance obtained at cathode is

Easy

A

0.2 g
B

0.05 g
C

0.025 g
D

0.1 g

Solution

SRP value of $E_{H^{+} (aq) / \frac{1}{2} H_{2} (1 atm), Pt (s)}^{o} > E_{K^{+} (aq) / K (s)}^{0}$
At cathode $H_{2}$ gas is liberated
$∴ W_{H_{2}} = \frac{Eit}{F} = \frac{Eq}{F} W_{H_{2}} = \frac{1 \times 9650}{96500} W_{H_{2}} = 0.1 g$

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