First slide

Electrolysis

Question

On electrolysis of dil. sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be :

Easy

A

Oxygen gas
B

$H_{2} S$ gas
C

${SO}_{2}$ gas
D

Hydrogen gas

Solution

$\begin{array}{l} H_{2} {SO}_{4} ⟶ 2 H^{+} + {SO}_{4}^{2 -} \\ (dilute) \\ Sulphate ion can never oxidise, sulphur in highest ox.state; At anode, 2 H_{2} O ⟶ 4 H^{+} + 4 e^{-} + O_{2} \end{array}$

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