First slide

Faraday's Laws

Question

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H₂ gas at the cathode is (1 Faraday = 96500 C mol^-1)

Moderate

Solution

Number of equivalents of H₂liberated = 0.01 x 2 =0.02
Number of coulombs required = No.of equivalents x 96500=0.02 x 96500 =1930 C
Number of coulombs = i x t sec =0.01 amp x t sec
$t = 1930 \times {10^2} = 19.3 \times {10^4}\sec$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App