Q.
Electrolysis of 50% H2SO4 produces
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a
H2S2O8at anode
b
H2 at anode
c
H2SO5 at cathode
d
Heavy water at anode
answer is A.
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Detailed Solution
H2SO4→ 2H++2HSO 4−Cathode:2H++2e−→ H2↑Anode:2HSO 4−→ H2S2O8+2e−H2S2O8+2H2O→ H2O2+H2SO4
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