Electrolysis of 50% H2SO4 produces

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H2S2O8at anode

H2 at anode

H2SO5 at cathode

Heavy water at anode

answer is A.

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Detailed Solution

H2SO4→ 2H++2HSO 4−Cathode:2H++2e−→ H2↑Anode:2HSO 4−→ H2S2O8+2e−H2S2O8+2H2O→ H2O2+H2SO4

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