First slide

Hydrogen Peroxide

Question

Electrolysis of X gives Y at anode. Vacuum distillation of Y gives H₂O₂. The number of peroxy (O–O) bonds present in X and Y respectively are :

Moderate

A

1,1
B

1,2
C

0,1
D

0, 0

Solution

$\therefore$ "X" is H₂SO₄ ⇒ CONATAINS "0" PEROXY BONDS
"Y" is H₂SO₄ ⇒ CONATAINS "1" PEROXY BONDS
AT CATHODE : 2H⁺ + 2e^- → H₂ ↑
[REDUCTION]

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